How can the conversion of (i) to (ii) be brought about?

K B r

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K B r + C H_{3} O N a

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K B r + K O H

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B r_{2} + K O H

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Solution

The correct option is D $B r_{2} + K O H$
During the conversion of (i) to (ii), an amide is converted to bromamide. The amide hydrogen is replaced with bromine. The reagents used for this conversion are $K O H$ and bromine. During the conversion, $H B r$ is formed as the side product which is neutralised by $K O H .$

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Similar questions

B r_{2}

I . C H_{3} C H_{2} C H_{2} B r + K O H \to C H_{3} C H = C H_{2} + K B r + H_{2} O

Which of the following statements is correct?

C H_{2} - B r + K O H \to C H_{3} O H + K B r

B r_{2}

K B r + C l_{2} ⟶ K C l + B r_{2}

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