Question

How can the numbers 6ⁿ Where n is a natural number end with digit 5 give reasons

Answer 1

No, 6^n cannot end with five.
For - "A ^ n" ( where A is any integer ), to end with 5 ( or have 5 in unit place ).
"A" must be in the form of 2 ^ m X 5 ^ n .
However, here 6 = 2 X 3
ie. 6 cannot be written in the form of 2^m X 5^n.
So, 6 ^n cannot end with five.