How can we calculate inverse tan for determining angle between vectors using Natural tangents table?
Let us find the inverse tan of 1.9430. Look through the values in the table of tangents. The nearest value you can find below it is 1.9375.
That's in the 63 degree row and in the 46 column. So it's the tangent of 63 deg 42 min. You need another 0.0055 to make that up to 1.9430, so look over in the difference column and find 55 (or the nearest to it). It should be in the 4 column, so add that 4 on to the minutes, giving the angle as 63 deg 46 min.