How can we convert an equation of motion into free fall?

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Solution

The equation of motion are valid for a body undergoing uniform acceleration, a.
$v = u + a t$
$s = u t + \frac{1}{2} a t^{2}$
$v^{2} = u^{2} + 2 a s$
During free fall, a body has constant acceleration of g.
Taking vertically downward as positive, the equations will become:
$v = u + g t$
$h = u t + \frac{1}{2} g t^{2}$
$v^{2} = u^{2} + 2 g h$

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