We will learn how to find the sum of the exterior angles of a polygon having n sides.
We know that, exterior angle + interior adjacent angle = 180°
So, if the polygon has n sides, then
Sum of all exterior angles + Sum of all interior angles = n × 180°
So, sum of all exterior angles = n × 180° - Sum of all interior angles
Sum of all exterior angles = n × 180° - (n -2) × 180°
= n × 180° - n × 180° + 2 × 180°
= 180°n - 180°n + 360°
= 360°
Therefore, we conclude that sum of all exterior angles of the polygon having n sides = 360°
Therefore, measure of each exterior angle of the regular polygon = 360°/n
Also, number of sides of the polygon = 360°/each exterior angle
Solved examples on sum of the exterior angles of a polygon:
1. Find the number of sides in a regular polygon when the measure of each exterior angle is 45°.
Solution:
If the polygon has n sides,
Then, we know that; n = 360°/measure of each exterior angle
= 360/45
= 8
Therefore, the regular polygon has 8 sides.