How can you explain higher stability of $B C l_{3}$ as compared to $T l C l_{3}$ ?

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Solution

B shows +3 oxidation state and can form stable $B C l_{3}$ . Thallium shows +1 and +3 oxidation state. Due to inert pair effect, +1 oxidation state is more stable than +3 oxidation state. Hence, $B C l_{3}$ is stable but $T l C l_{3}$ not.

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