How can you express 997 so that the expression $997^{2}$ can be calculated using an algebreaic identity?

$990 + 7$

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$995 + 2$

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$1000 - 3$

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$1005 - 8$

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Solution

The correct option is C
$1000 - 3$

Whenever a number close to a power of 10 is given, we choose the respective power of 10 as the first number.
Here, 1000 will be the first number. This is because $1000^{2}$ is easy to calculate.
The second number will be 3 since 997 is 3 less than 1000.
Thus the expression is
$997 = 1000 - 3$ .

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How can you express 997 so that the expression $997^{2}$ can be calculated using an algebreaic identity?