How can you lower a $100 k g$ body from the roof of a house using a cord with a breaking strength of $80 k g$ weight without breaking the rope? ( $1 k g w e i g h t = g N$ )

1.96 m / s^{2}

downwards

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9.8 m / s^{2}

downwards

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98 m / s^{2}

downwards

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19.6 m / s^{2}

downwards

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Solution

The correct option is A $1.96 m / s^{2}$ downwards
REF.Image.
The FBD of situation will be as
So, the transitional $e q^{n}$ will be
Mg - T max = ma
$\Rightarrow 100 g - 80 g = (100) a$
$\Rightarrow \frac{20}{100} g = a$
As $g = 9.8 m / s^{2}$
$a = 0.2 \times 9.8 m / s^{2} = 1.96 m / s^{2}$
It is acting downwards
Option -A is correct.

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How can you lower a 100 kg body from the roof of a house using a cord with a breaking strength of 80 kg weight without breaking the rope? (1 kg weight=g N)

The correct option is A 1.96 m/s2 downwardsREF.Image.The FBD of situation will be asSo, the transitional eqn will beMg - T max = ma⇒100g−80g=(100)a⇒20100g=aAs g=9.8m/s2a=0.2×9.8m/s2=1.96m/s2It is acting downwardsOption -A is correct.

How can you lower a $100 k g$ body from the roof of a house using a cord with a breaking strength of $80 k g$ weight without breaking the rope? ( $1 k g w e i g h t = g N$ )