You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nomenclature of Carbonyls

How CO2 rea...

Question

How $C O_{2}$ realised is identified, when $N a_{2} C O_{3}$ is treated with dilute $H_{2} S O_{4}$ ?

Brisk effervescences

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O_{2}

turns lime water milky

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both

A

and

B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Burns with a pop sound

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Both $A$ and $B$
When sodium carbonate is treated with dilute $H_{2} S O_{4}, C O_{2}$ is released which gives brisk effervescence. The gas evolved can be identified using lime water as $C O_{2}$ turns lime water milky.
$N a_{2} C O_{3} + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O + C O_{2}$

Suggest Corrections

Similar questions

100 g

112 %

H_{2} S O_{4}

5.3 g

N a_{2} C O_{3}

C O_{2}

300 K

H_{2} S O_{4} + N a_{2} C O_{3} \to N a_{2} S O_{4} + H_{2} O + C O_{2}

X

{C O}_{2}

{C O}_{2}

X

C O_{2}

C O_{2}

C O_{2}

H_{2} S O_{4}

(X)

C O_{2}

C O_{2}

(X)

Join BYJU'S Learning Program