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Question

How do we calculate the oxidation number of polyatomic ion?


A

Add individual negative oxidation numbers only and calculate final value

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B

Add individual oxidation numbers and calculate final value as polyatomic ion oxidation number

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C

Add individual positive oxidation numbers only and calculate final value

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D

None of the choices

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Solution

The correct option is B

Add individual oxidation numbers and calculate final value as polyatomic ion oxidation number


The sum of the oxidation numbers of the atoms present in a polyatomic ion is equal to the charge of the ion.

Individual ionic oxidation numbers are added up and the resultant balance number is taken as final oxidation number.

SO42

S = + 6 and O = - 2 (oxidation numbers)

(+6) + [(-2) * (4)] = (+6) + (-8) = - 2


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