Question

How do we divide $81$ into two parts so that one may be a a multiple of 5 and the other of 8.

• A. $79$ and $2$
• B. $25$ and $56$
• C. $16$ and $65$
• D. $49$ and $32$

Answer 1

Answer: (B), (C)

The correct options are
B $25$ and $56$
C $16$ and $65$

Let $5x+8y=81$

We will find x and y such that it satisfies above equation

y must be less than $10$ to satisfy above equation

X must be less than $17$ to satisfy the above equation

Let we go by options

1st option is not correct as $2$ is not a multiple of $8$

2nd and 3rd options are correct because it satisfies above conditions