How do you calculate log -10 -2- - Maths Q-A

Calculate the given expressionGiven expression: log_10(2).It is known that 𝐥𝐨𝐠_𝐛(a)=𝐥𝐧(𝑎)/𝐥𝐧(𝑏) .Thus, log_10(2)=ln(2)/ln(10)=0.69315/2.30258=0.301.Therefore, l ...

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Standard XI

Mathematics

Sum of Infinite Terms of a GP

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Question

How do you calculate $\log_{10} (2)$ ?

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Solution

Calculate the given expression
Given expression: $\log_{10} (2)$ .
It is known that $\log_{b} (a) = \frac{\ln (a)}{\ln (b)}$ .
Thus, $\log_{10} (2) = \frac{\ln (2)}{\ln (10)} = \frac{0.69315}{2.30258} = 0.301$ .
Therefore, $\log_{10} (2) = 0.301$ .

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How do you calculate log102?

Calculate the given expressionGiven expression: log102.It is known that logb(a)=ln(a)ln(b) .Thus, log102=ln2ln10=0.693152.30258=0.301.Therefore, log10(2)=0.301.

How do you calculate $\log_{10} (2)$ ?

Calculate the given expression
Given expression: $\log_{10} (2)$ .
It is known that $\log_{b} (a) = \frac{\ln (a)}{\ln (b)}$ .
Thus, $\log_{10} (2) = \frac{\ln (2)}{\ln (10)} = \frac{0.69315}{2.30258} = 0.301$ .
Therefore, $\log_{10} (2) = 0.301$ .