How do you calculate the $p H$ of the solution when given the $[O H^{-}]$ concentration?

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Solution

We know that, $p H + p O H = 14$

Thus for a given $[O H^{-}]$ concentration,
$p O H = - l o g_{10} [O H^{-}]$

Thus we got the value of pOH, substituting it in $p H = 14 - p O H$ ,
$p H = 14 + l o g_{10} [O H^{-}]$

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