0.¯¯¯¯¯¯63=711 and 0.6¯3=1930
Explanation :
I will use bar notation to indicate repeating digits, placing a bar over the sequence of digits which is repeated...
0.63636363.... =0.¯¯¯¯¯¯63
If we multiply this repeating decimal by (100−1) then we will get an integer: Multiplying by 100 shifts the number left by 2 places (the length of the repeating pattern), then we subtract the original number to cancel out the repeating tail...
(100−1)0.¯¯¯¯¯¯63=63.¯¯¯¯¯¯63=0.¯¯¯¯¯¯63=63
Then divide both sides by (100−1) and simplify :
0.¯¯¯¯¯¯63=63100−1=6399=7⋅911⋅9=711
On second thoughts, may be you meant 0.6¯¯¯3, in which case.
Multiply by 10(10−1) to get an integer. The first 10 shifts the number left one place, to leave the repeating pattern starting just after the decimal point. The (10−1) shifts the number one more place (the length of the repeating pattern) to the left, then subtracts the original to cancel out the repeating tail...
10(10−1)0.6¯¯¯3=63.¯¯¯3−6.¯¯¯3=57
Then divide both sides by 10(10−1)=100−10=90 and simplify :
0.6¯¯¯3=5710(10−1)=5790=19⋅330⋅3=1930