How do you evaluate sec150° ?
Compute the required value.
We know that, sec180°-θ=-secθ.
150 can be written as 180-30.
Thus, sec150°=sec180°-30°
=-sec30°=-23
Hence, the value of sec150° is -23.
How do you evaluate log0.0110
How do you evaluate sin3π2?
How do you evaluate and simplify 2723?