How do you express sinx2 in terms of cosxusing the double angle identity?
Expressing sinx2 in terms of cosx:
By using the trigonometry identity
cos2a=1−2sin2a,
⇒cosx=1-2sin2x2⇒2sin2x2=1-cosx⇒sin2x2=1-cosx2⇒sinx2=±1-cosx2
Hence, sinx2=±1-cosx2 is the required value.
Express sinx2 in terms of cosx using the double angle identity.
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