How do you factor $x^{2} - 11 x + 30$ ?

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Solution

$(x - 5) (x - 6)$
Explanation:
This is a quadratic equation in the form of $a x^{2} + b x + c,$
so you simply factor $b$ into two parts such that their sum is $b$
and product is ac.
$x^{2} - 11 x + 30$
$x^{2} - 5 x - 6 x + 30$
$(- 5 \times - 6 = 30$ and $- 5 - 6 = - 11)$
$x (x - 5) - 6 (x - 5)$
$(x - 5) (x - 6)$

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