Question

How do you factor $x^3-1$ ?

Answer 1

$(x-1)(x^2+x+1)$
Explanation:
$x^3-1$ is a difference of cubes
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Here, $a=x$ and $b=1$
$x^3-1=(x-1)(x^2+x+1)$