How do you find g(3) given g(x)=x2-x
Value of polynomial:
Substitute the value in the given function to compute g(3).
Given a function g(x)=x2-x.
Substitute x=3 in the function,
g(x)=x2-x⇒g(3)=32-3⇒g(3)=9-3⇒g(3)=6
Hence, the value is g(3)=6.
Use the factor theorem to determine whether g(x) is a factor of f(x)
f(x)=22x2+5x+2;g(x)=x+2
Given f(x)=x(−6), how do you find f(9)?
Given gx=-2x2-9, how do you find g3?