Question

How do you find the diagonal of a rectangle whose sides are $20$ and $48$?

Answer 1

Solve for diagonal:

Given: length$=20$ and breadth$=48$

The angles of the rectangle are of $90°$. so, we can apply the Pythagoras theorem.

Assume that, the diagonal of the rectangle is $x$.

$$\begin{gathered} x^2=l^2+b^2 \\ \Rightarrow x^2={\left(20\right)}^2+{\left(48\right)}^2 \\ \Rightarrow x^2=2704 \\ \Rightarrow x=52 \end{gathered}$$

Hence, the diagonal of the rectangle is $52$.