Question

How do you find the midpoint of $A(-1,5),B(6,-3)$?

Answer 1

Solve for the required midpoint:

Given that, $A(-1,5),B(6,-3)$

We know that the midpoint of points $\left(x_1,y_1\right)$ and $\left(x_2,y_2\right)$ is $\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$

Here $(x_1,y_1)=(-1,5)$ and $(x_2,y_2)=(6,-3)$

$\Rightarrow$Midpoint of $AB=$ $\left(\frac{-1+6}{2},\frac{5+(-3)}{2}\right)$

$=\left(\frac{5}{2},\frac{2}{2}\right)$$=\left(\frac{5}{2},1\right)$

Hence, the midpoint of the given points is $\left(\frac{5}{2},1\right)$.