How do you integrate ∫1x2dx.
Evaluate the integration:
The given integration is,
∫1x2dx=∫x-2dx
=x-2+1-2+1+c [∵∫xndx=xn+1n+1]
=-x-1+c
=-1x+c [cbetheintegrationconstant]
Hence, the required answer is -1x+c.