Question

How do you order the following from least to greatest.

$\sqrt{\frac{7}{2}},\sqrt{11},-\sqrt{16},-3.3,-\sqrt{36}$?

Answer 1

Determine to find the order of $\sqrt{\frac{7}{2}},\sqrt{11},-\sqrt{16},-3.3,-\sqrt{36}$ from least to greatest.

Conversion of the given values into decimals as written as,

$\sqrt{\frac{7}{2}}$	$\sqrt{11}$	$-\sqrt{16}$	$-3.3$	$-\sqrt{36}$
$1.8708$	$3.3166$	$-4$	$-3.3$	$-6$

Now arrange them in order from smallest to largest:

$-6<-4<-3.3<1.8708<3.3166$

Therefore, the order from smallest to largest is written as $\mathbf{-}\sqrt{\mathbf{36}}\mathbf{,}\mathbf{}\mathbf{-}\sqrt{\mathbf{16}}\mathbf{,}\mathbf{}\mathbf{-}\mathbf{3}\mathbf{.}\mathbf{3}\mathbf{,}\mathbf{}\sqrt{\frac{\mathbf{7}}{\mathbf{2}}}\mathbf{,}\mathbf{}\sqrt{\mathbf{11}}$.