Question

How do you simplify ${\left(\frac{2}{3}\right)}^{-1}$?

Answer 1

Simplify the required term.

As we know, $x^{-1}=\frac{1}{x}$

Thus, ${\left(\frac{2}{3}\right)}^{-1}$can be written as $\frac{1}{\left({\displaystyle \frac{2}{3}}\right)}$.

$\Rightarrow {\left(\frac{2}{3}\right)}^{-1}=\frac{3}{2}$

Hence, ${\left(\frac{2}{3}\right)}^{-1}$can be simplified as $\frac{3}{2}$.