Question

How do you simplify $\sqrt{128}+\sqrt{32}$ ?

Answer 1

To simplify the given expression $\sqrt{128}+\sqrt{32}$:

Simplifying the above expression:

$\begin{array}{rcl}\sqrt{128}+\sqrt{32}& =& \sqrt{64\times 2}+\sqrt{16\times 2}\left[\text{Break into prime factor}\right]\\ & \Rightarrow & \sqrt{128}+\sqrt{32}=8\sqrt{2}+4\sqrt{2}\left[\text{Take out numbers from square root}\right]\\ \therefore \sqrt{128}+\sqrt{32}& =& 12\sqrt{2}\left[\text{Add like terms}\right]\end{array}$

Hence, the answer is $\mathbf{12}\sqrt{\mathbf{2}}$.