Question

How do you solve for $f$ in $C=\frac{5}{9}\left(f-32\right)$.

Answer 1

Explanation:

Converting $f$ in terms of $C$ :

Given, $C=\frac{5}{9}\left(f-32\right)$

$$\begin{gathered} \Rightarrow 9C=5\left(f-32\right)\left(\text{Cross multiplication}\right) \\ \Rightarrow \frac{9}{5}C=f-32 \\ \Rightarrow f=\frac{9}{5}C+32 \end{gathered}$$

Hence, $f=\frac{9}{5}C+32$.