How do you solve for $x$ in $2 x + 3 y = 6$ ?

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Solution

Find the value of $x$ in $2 x + 3 y = 6$
Separate $x$ term from rest of the terms
$2 x + 3 y = 6$
$\Rightarrow$ $2 x = 6 - 3 y$
$\Rightarrow$ $x = \frac{6 - 3 y}{2}$
$\Rightarrow$ $x = 3 - \frac{3 y}{2}$
Hence the value of $x$ is $3 - \frac{3 y}{2}$

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