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Standard Logarithm

How do you So...

Question

How do you Solve for $x : l o g_{5} (4 x - 3) = 2$ ?

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Solution

Remember: $l o g_{b} a = c$ means $b^{c} = a$
So $l o g_{5} (4 x - 3) = 2$
means $5^{2} = 4 x - 3$
$\Rightarrow 25 = 4 x - 3$
$\Rightarrow 28 = 4 x$
$\Rightarrow 7 = x$

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