How do you solve for $y$ in $3 x + 2 y = 12$ ?

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Solution

Find the value of $y$ .
The given equation is $3 x + 2 y = 12$ .
Now subtract the equation with $3 x$ on both sides.
$2 y = 12 - 3 x$
Simplify further by dividing $2$ on both sides:
$\begin{array}{rcl} \frac{2 y}{2} & = & \frac{12 - 3 x}{2} \\ \Rightarrow & y = \frac{12 - 3 x}{2} \\ \Rightarrow & y = - \frac{3}{2} x + 6 \end{array}$
Therefore, the value of $y$ in $3 x + 2 y = 12$ is $- \frac{3}{2} x + 6$ .

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