Question

How do you solve $\frac{4}{3}s-3<s+\frac{2}{3}-\frac{1}{3}s$?

Answer 1

Solve for the required value:

We will use transpose entity to solve the given expression

$\frac{4}{3}s-3<s+\frac{2}{3}-\frac{1}{3}s$

$\Rightarrow$ $\frac{4}{3}s+\frac{1}{3}s-s<\frac{2}{3}+3$ [Transposing $s$ and $-\frac{1}{3}s$ to the left and $-3$ to the right]

$\Rightarrow$ $\frac{\left(4+1-3\right)}{3}s<\frac{2+9}{3}$

$\Rightarrow$ $\frac{2}{3}s<\frac{11}{3}$

$\Rightarrow$ $2s<11$

$\Rightarrow$ $s<\frac{11}{2}$

Hence, the required value is $s<\frac{11}{2}.$