Question

How do you solve $\frac{5\mathrm{x}-3}{4}=7$?

Answer 1

Step-1: Eliminate the fraction:

Given equation: $\frac{5\mathrm{x}-3}{4}=7$

Multiply by $4$ on both sides to eliminate the fraction

$\begin{array}{rl}& \Rightarrow 4\times \frac{5x-3}{4}=4\times 7\\ & \Rightarrow 5x-3=4\times 7\\ & \Rightarrow 5x-3=28\end{array}$

Step-2: Eliminate $3$ in the L.H.S :

Add $3$ on both sides of the equation to eliminate $3$ in the L.H.S

$$\begin{gathered} \Rightarrow 5\mathrm{x}-3+3=28+3 \\ \Rightarrow 5\mathrm{x}=31 \end{gathered}$$

$\Rightarrow \mathrm{x}=\frac{31}{5}$

Hence, the solution for the equation $\frac{5\mathrm{x}-3}{4}=7$ is $\mathrm{x}=\frac{31}{5}$.