How do you solve x2-x=90?
Find the value of x:
Given equation is x2-x=90
∴x2-x-90=0⇒x2-10x+9x-90=0⇒x(x-10)+9(x-10)=0⇒(x-10)(x+9)=0
⇒x=10 or x=-9
Therefore, the solutions of x2-x=90 are x=10 or x=-9.
How do you solve x2=90?
How do you solve 2x=64?
How do you solve 4x=16?
How do you solve logx=-2?