How do you write $4 x - y - 7 = 0$ in slope intercept form?

Open in App

Solution

Write the given equation in slope-intercept form:
Slope-intercept is represented in the form of $y = m x + c$ , where, $m$ is the slope and $c$ is the intercept.
Here, the given equation of the straight line is $4 x - y - 7 = 0$ .
Add $7$ to both sides of the equation:
$4 x - y - 7 + 7 = 7 \Rightarrow 4 x - y = 7$
Subtract $4 x$ from each side:
$\Rightarrow 4 x - y - 4 x = 7 - 4 x \Rightarrow - y = 7 - 4 x$
Multiply $- 1$ to each side:
$\begin{array}{rcl} \Rightarrow & (- y) \times (- 1) = (7 - 4 x) \times (- 1) \\ \Rightarrow & y = 4 x - 7 \end{array}$
Hence, the slope-intercept form of the equation $4 x - y - 7 = 0$ is $y = 4 x - 7$ .

Suggest Corrections

Similar questions

Reduce the following equations into slope-intercept form and find their slopes and the y-intercepts.

(i) x + 7y = 0 (ii) 6x + 3y – 5 = 0 (iii) y = 0

How do you do slope intercept form?

How do you write an equation of a line with slope $3$ and $y -$ intercept $6$ ?

How do you interpret the slope and $y$ -intercept $?$

How do you find the slope and y-intercept of the line $- 7 x - 9 y = 27$ ?

Join BYJU'S Learning Program