Question

How do you write $x^2-2x=8$ in standard form?

Answer 1

Find quadratic form:

The standard quadratic form is given by: $a{x}^2+bx+c=0$, where $a,b,c$ are real numbers.

Here, given that: $x^2-2x=8$. To make it standard, subtract $8$ on both sides of the equation $x^2-2x=8$ and get:

$$\begin{gathered} x^2-2x-8=8-8 \\ \Rightarrow x^2-2x-8=0 \end{gathered}$$

Therefore, the standard form of $x^2-2x=8$ is $x^2-2x-8=0$, where $a=1,b=-2,c=-8$.

Hence, standard form is $x^2-2x-8=0$.