How does doubling number of turns in a toroidal coil affect the value of magnetic flux density ?
A
Four times
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B
Eight times
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C
Half
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D
Double
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Solution
The correct option is D Double Magnetic field due to a toroidal coil of radius r having n turns and carrying a current i is given by: B=μ0ni/2πr. So B is proportional to n. If we doubled the number of turns then the field will be also doubled.