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How does Na2C...

Question

How does Na₂CO₃ help in removing hardness of water?

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Solution

Permanent hardness in water can be removed by adding washing soda. This removes the hardness creating chloride and sulphate of Ca and Mg.
$M g C l_{2} + N a_{2} C O_{3} \to M g C O_{3} + 2 N a C l C a C l_{2} + N a_{2} C O_{3} \to C a C O_{3} + 2 N a C l M g S O_{4} + N a_{2} C O_{3} \to M g C O_{3} + N a_{2} S O_{4}$
Thus the soluble chloride and sulphate of Ca or Mg is converted as precipitate and is filtered.

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Similar questions

Q. Washing soda helps in removing the permanent hardness of water.

Q. Permanent hardness is due to

S O_{4}^{2 -}

C l^{-}

C a^{2 +}

M g^{2 +}

and is removed by the addition of

N a_{2} C O_{3}

.

C a S O_{4} + N a_{2} C O_{3} ⟶ C a C O_{3} + N a_{2} S O_{4}

C a C l_{2} + N a_{2} C O_{3} ⟶ C a C O_{3} + 2 N a C l

100

C a C O_{3}

N a_{2} C O_{3}

required to soften

10

L of hard water is :

Q. What mass of

N a_{2} C O_{3}

is required to remove hardness in above problem.

10

L of hard water required

0.56

(C a O)

for removing hardness. Hence, temporary hardness in ppm of

C a C O_{3}

C a S O_{4}

causes permanent hardness in water. It can be removed by precipitating it as

C a C O_{3}

N a_{2} C O_{3}

. If the amount of

N a_{2} C O_{3}

required to soften 100 L of hard water, which is 200 ppm

C a C O_{3}

x

g, then value of

x

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