Question

How does the angle of dip vary as one moves from the equator towards the north pole.If the horizontal component of earth's magnetic field at a place when a angle of dip is ${60}^{\circ }$ is $0.4\times {10}^{-4}T$.Calculate the vertical component and the resultant magnetic field of the earth at the point.

Answer 1

$BH=0.4\times {10}^{-4}T$

$8={60}^o$

$\frac{BV}{BH}=\tan {60}^o$

$Br=BH\tan {60}^o$

$=.6928\times {10}^{-4}T$