How does the angle of minimum deviation produced by a prism change with increase in the refracting angle of prism?

i n c r e a s e s

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d e c r e a s e s

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r e m a i n s s a m e

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i n c r e a s e s t h e n d e c r e a s e s

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Solution

The correct option is B $d e c r e a s e s$
$δ_{m} = 2 i - A$
Therefore, with increase in angle of prism $A$ the angle of deviation $δ$ decreases.

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Similar questions

How does the angle of minimum deviation produced by a prism change with increase in (i) the wavelength of incident light, and (ii) the refracting angle of prism?

Q. How does the angle of minimum deviation produced by a prism change with increase in the wavelength of incident light

Q. Consider the following statements A and B and identify the correct choice
A) For a given value of angle of incidence, the angle of deviation produced by a prism increases with increasing of refractive index of the prism
B) Angle of deviation produced by a thin prism is independent of angle of incidence

(a) How does the angle of deviation produced by a prism change with an increase in the angle of incidence? Draw a curve showing the variation in the angle of deviation with the angle of incidence at a prism surface.

(b) Using the curve in part (a) above, how do you infer that for a given prism, the angle of minimum deviation $δ_{m i n}$ is unique for the given light.

Q. The angle of deviation decreases with increase in the angle of prism.

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How does the angle of minimum deviation produced by a prism change with increase in the refracting angle of prism?

The correct option is B decreasesδm=2i−ATherefore, with increase in angle of prism A the angle of deviation δ decreases.

The correct option is B $d e c r e a s e s$
$δ_{m} = 2 i - A$
Therefore, with increase in angle of prism $A$ the angle of deviation $δ$ decreases.