Question

how does the k.e of a body change if its momentum of is doubled?

Answer 1

KE=1/2mv^2

Multiply and divide by m

$KE=0.5(mv{)}^2/m$

$KE=0.5p^2/m(Sincep=mv)$

So KE is directly proportional to $p^2$

Hence if momentum is doubled then KE increases by 4 times