How does the method used for extracting a metal from its ore depend on the metal's position in the reactivity series ? Explain with examples.

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Solution

This is because the extraction of a metal from its concentrated ore is essentially a process of reduction of the metal compound present in the ore. For example: Manganese metal is obtained by the reduction of its oxide with aluminium powder and not carbon. This is because carbon is less reactive than manganese. Aluminium is more reactive than carbon.

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Similar questions

Q. How does the method used for extracting a metal from its ore depend on the metal's position in the reactivity series? Explain with examples.

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How is the method of extraction of metal high up in the reactivity series different from that for metals in the middle? Why the same process can't be applied for them ? Explain giving equations the extraction of sodium?

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The methods for extracting metals from their ores are:

1. roasting a metal sulphide

2. chemical reduction of a metal oxide

3. electrolysis,

The preferred method depends on

E^{\circ}

value for the reducing half-reaction:

$M^{n +} (a q) + n e^{-} \to M (s)$

Which method is preferred for the metals with the most positive

E^{\circ}

values?

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