How does the refractive index of a transparent medium depend on the wavelength of incident light? Velocity of light in glass is 2 x 108 m/s. calculate the value of critical angle and polarizing angle of glass.

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Solution

dear student
$η (r e f r a c t i v e i n d e x) = \frac{s p e e d o f t h e l i g h t i n v a c c u m}{s p e e d o f l i g h t i n m e d i u m} = \frac{f λ_{v a c u u m}}{f λ_{m e d}} = \frac{λ_{v a c u u m}}{λ_{m e d i u m}} η = \frac{3 \times 10^{8}}{2 \times 10^{8}} = 1.5 c r i t i c a l a n g l e = \sin c = \frac{1}{η} = \frac{2}{3} t h u s c = 42 d e g r e e f o r p o l a r i z i n g a n g l e \tan θ = \frac{1}{η} = \frac{2}{3} θ = 33.8 d e g r e e$

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How does the refractive index of a transparent medium depend on the wavelength of incident light? Velocity of light in glass is 2 x 108 m/s. calculate the value of critical angle and polarizing angle of glass.

dear student η(refractive index)=speed of the light in vaccumspeed of light in medium=fλvacuumfλmed=λvacuumλmediumη=3×1082×108=1.5critical angle =sinc =1η=23thus c=42 degreefor polarizing angletanθ=1η=23θ=33.8degree