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Many-One into Function

How f x +Δ x ...

Question

How f(x+Δx)-f(x) change to (x+Δx) ^2 -x^2. ????? Calculus

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Solution

In this type of questions,we will get the relation between f(x) and x
here we may give f(x)=x^2
then only we can proceed this type of questions
Thats why( f(x+Δx)= (x+Δx)^2

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Similar questions

f (x) = \frac{x^{2}}{2} + 3 x

x = 2, δ x = 0.05

d f = ?

f (x) = 3 x^{2} - x

x = 1

δ x = 0.02

δ f =

f (x), g (x)

h (x)

are three polynomial of degree

2

Δ (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} f (x) & g (x) & h (x) f^{'} (x) & g^{'} (x) & h^{'} (x) f^{''} (x) & g^{''} (x) & h^{''} (x) \end{matrix} ∣ ∣ ∣ ∣ ∣

Δ (x)

is a polynomial of degree

\leq 2

, if true enter 1 else 0.

f (x), g (x)

h (x)

are three polynomials of degree

2

Δ (x) ∣ ∣ ∣ ∣ ∣ \begin{matrix} f (x) f^{'} (x) f " (x) \end{matrix} \begin{matrix} g (x) g^{'} (x) g " (x) \end{matrix} \begin{matrix} h (x) h^{'} (x) g " (x) \end{matrix} ∣ ∣ ∣ ∣ ∣

then polynomial of degree (whenever defined)

Δ (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x - 2 & (x - 1)^{2} & x^{3} x - 1 & x^{2} & (x + 1)^{3} x & (x + 1)^{2} & (x + 2)^{3} \end{matrix} ∣ ∣ ∣ ∣ ∣

, find the absolute value of coefficient of

x

Δ (x)

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