Question

How far does the runner whose time-velocity graph is shown in the figure travel in 16 seconds ?

Answer 1

From the above figure,

Area under v-t graph gives displacement.

Area of $\Delta ABC=\frac{1}{2}\times 2\times 8=8m$

Area of square ABMX

$={\left(side\right)}^2$

$={\left(8\right)}^2$

$=64m^2$

Area of $\Delta BDC=\frac{1}{2}\times 2\times 4=4m^2$

Area of rectangle $MNCD=2\times 4=8m^2$

Area of square NQPC

$={\left(4\right)}^2$

$=16m^2$

So, the displacement is

$s=64+8+4+8+16$

$s=100m$