Question

How fast should a man of 50 kg run so that his kinetic energy be 625 j ?

Answer 1

K.E=$1/2m{v}^2$

625=$1/2\times 50v^2$

625 =$25v^2$

$v^2$=625/25

$v^2$=25

v = √25

v = 5m/s