how Fe3O4 is formed, oxygen doesn't have the valency 3 then how it's Fe3O4

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Solution

$F {e_{3}} O_{4}$ is a double oxide, i.e, a mixed oxide consisting of FeO and $F e_{2} O_{3}$ with a valency of iron 2 & 3 respectively, and that of oxygen is 2.

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Why is the chemical formula of iron oxide Fe₃O₄ when the valency of iron is 2,3 and that of oxygen is 2

How many valence electrons does oxygen have?

(F e_{3} O_{4})

F e_{3} O_{4} + 4 C O \to 3 F e + 4 C O_{2}

F e_{3} O_{4}

N a_{2} S_{4} - - - O_{6}, N a_{2} S_{2} - - - O_{3}, C a O C l_{2} - -- -, N_{2} - - - H_{4} O_{3}, F e_{3} - -- - O_{4}, K I_{3} - -, C r O_{5} - - -, K_{2} C r_{2} - -- - O_{7}

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