The correct option is C 1326
Velocity of missile at a height 1000 m, u=80 m/s
Let say the missile go further h meter high after the engine stops.
Final velocity at that position v=0
Acceleration due to gravity g=−9.8 m/s2
Using v2−u2=2gh
∴ 0−802=2(−9.8)h
⟹ h=326 m
Thus maximum height achieved by the missile Hmax=1000+326=1326 m