How is a perimeter 'p' related to a semi-perimeter 's' of a triangle?

p=s/2

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p = 2s

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p=s

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p=s²

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Solution

The correct option is B
p = 2s

The perimeter of a triangle = a + b + c, where a, b and c are the lengths of the sides of a triangle.
The semi-perimeter of a triangle = $\frac{a + b + c}{2}$ , here a, b and c are also the lengths of the sides of a triangle.
Thus, the perimeter of a triangle is 2 $\times$ the semi-perimeter of a triangle, i.e., p = 2s.

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