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Potassium Permanganate

How is Cl2 ...

Question

How is $C l_{2}$ prepared using $K M n O_{4}$

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Solution

$K M n O_{4}$ when reacted with $H C l$ gives $C l_{2}$
The reaction is given by,
$K M n O_{4} + H C l \to K C l + M n C l_{2} + H_{2} O + C l_{2}$

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