Question

How is ethyl acetate prepared form?
(a) Silver acetate
(b) Acetic anhydride
(c) Acetyl chloride?

Answer 1

(a) Silver acetate reacts with ethyl iodide to give ethyl acetate and silver iodide.
$\underset{Silveracetate}{C{H}_{3}CO{O}^{-}A{g}^{+}}+\underset{\underset{iodide}{Ethyl}}{C_2{H}_{5}I}\stackrel{\Delta }{\to }\underset{\underset{acetate}{Ethyl}}{C{H}_{3}COO{C}_2{H}_5}+\underset{\underset{iodide}{Silver}}{AgI}\downarrow$

(b) Acetic anhydride reacts with ethanol to give ethyl acetate and acetic acid.
$\underset{\underset{anhydride}{Acetic}}{(C{H}_{3}CO{)}_{2}O}+\underset{Ethanol}{C_2{H}_{5}OH}\to \underset{\underset{acetate}{Ethyl}}{C{H}_{3}COO{C}_2{H}_5}+\underset{\underset{acid}{Acetic}}{C{H}_{3}COOH}$

(c) Acetyl chloride reacts with ethanol to give acetate and hydrogen chloride.
$\underset{\underset{chloride}{Acetyl}}{C{H}_{3}COCl}+\underset{Ethanol}{C_2{H}_{5}OH}\to \underset{\underset{acetate}{Ethyl}}{C{H}_{3}COO{C}_2{H}_5}+\underset{\underset{chloride}{Hydrogen}}{HCl}$