How is ethyl amine prepared from methyl iodide?

Open in App

Solution

Methyl iodide is treated with NaCN to form acetonitirle. Acetonitrle is reduced with Na/ ethanol to form ethyl amine. This reaction is called Mendius reduction.
$C H_{3} - I + N a C N \to C H_{3} - C N + N a I$
$C H_{3} - C N N a / e t h a n o l - ------ \to C H_{3} - C H_{2} - N H_{2}$

Suggest Corrections

Similar questions

How are methane and ethane prepared from methyl iodide and ethyl bromide ?

Name the compound prepared from :
(a) sodium propionate, (b) methyl iodide and
(c) ethyl bromide.
Write a balanced equation for the same.

Join BYJU'S Learning Program